Home > Backend Development > PHP Tutorial > php用正则表达式截取字符

php用正则表达式截取字符

WBOY
Release: 2016-06-13 13:49:32
Original
974 people have browsed it

php用正则表达式截取字符【求助】
哪位高手帮忙看看:我想从下面的代码中提取
{dede:field name='keywords'}{/dede:field}
{dede:field name='description'}{/dede:field}
{dede:field name='title'}http://down.sucai.com/fonts/soft/071130/1_071204075903.rar{/dede:field}
{dede:field name='writer'}{/dede:field}
{dede:field name='source'}{/dede:field}
{dede:field name='body'}{/dede:field}
{dede:field name='pubdate'}{/dede:field}
{dede:field name='litpic'}/uploads/allimg/c100112/12632b9420Z-412413.jpg{/dede:field}
这个
http://down.sucai.com/fonts/soft/071130/1_071204075903.rar

/uploads/allimg/c100112/12632b9420Z-412413.jpg
正则应该怎么来写呢

------解决方案--------------------

PHP code
 <br> $str =   {dede:field name='keywords'}{/dede:field} <br> {dede:field name='description'}{/dede:field} <br> {dede:field name='title'}http://down.sucai.com/fonts/soft/071130/1_071204075903.rar{/dede:field} <br> {dede:field name='writer'}{/dede:field} <br> {dede:field name='source'}{/dede:field} <br> {dede:field name='body'}{/dede:field} <br> {dede:field name='pubdate'}{/dede:field} <br> {dede:field name='litpic'}/uploads/allimg/c100112/12632b9420Z-412413.jpg{/dede:field} <br> EOF; <br>  <br> preg_match_all("#name='(title|litpic)'\}(.*)\{#U",$str,$matches); <br>  <br> print_r($matches); <br> 
Copy after login

------解决方案--------------------
$s = {dede:field name='keywords'}{/dede:field} 
{dede:field name='description'}{/dede:field} 
{dede:field name='title'}http://down.sucai.com/fonts/soft/071130/1_071204075903.rar{/dede:field} 
{dede:field name='writer'}{/dede:field} 
{dede:field name='source'}{/dede:field} 
{dede:field name='body'}{/dede:field} 
{dede:field name='pubdate'}{/dede:field} 
{dede:field name='litpic'}/uploads/allimg/c100112/12632b9420Z-412413.jpg{/dede:field} 
HTML;

$p = '#}(.+){#';

preg_match_all($p, $s, $r);
print_r($r[1]);


Array
(
[0] => http://down.sucai.com/fonts/soft/071130/1_071204075903.rar
[1] => /uploads/allimg/c100112/12632b9420Z-412413.jpg
)
Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template