取子串的正则表达式,该怎么处理

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Release: 2016-06-13 13:49:30
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取子串的正则表达式
有如下字符串:
"name1name2"
用正则表达式如何取出"name1"和"name2"呢?谢谢

------解决方案--------------------

PHP code
<?php $str = "<str1>name1<str2>name2</str2>";
$patten  = "/<str>([^/isU";
preg_match_all($patten,$str,$matches);
print_r($matches[1]);
<br><font color="#e78608">------解决方案--------------------</font><br><dl class="code">PHP code<pre class="brush:php;toolbar:false">

$str = "<str1>name1</str1><str2>name2</str2>";
preg_match_all('/>([^ name1 [1] => name2 ) 
*/
<br><font color="#e78608">------解决方案--------------------</font><br>
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PHP code
preg_match_all("/>[^<font color="#e78608">------解决方案--------------------</font><br>$str = "<str1>name1</str1><str2>name2</str2>";<br>preg_match_all('/>([^print_r($matches[1]);<br>/**<br>输出结果:<br>Array ( [0] => name1 [1] => name2 )  <br>*/<br>
<br><font color="#e78608">------解决方案--------------------</font><br>
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PHP code

<?php $str="<str1>name1<str2>name2</str2>";
    $preg="#<str1>(.*)</str1><str2>(.*)</str2>#";
    preg_match($preg,$str,$arr);
    echo $arr[1];
    echo $arr[2];
?>
<br><font color="#e78608">------解决方案--------------------</font><br><?php <br />   $str="<str1>name1</str1><str2>name2</str2>";<br>   preg_match_all("/([^]*)/",$str,$matches);<br>   echo $matches[1][0];<br>   echo $matches[1][1];<br>?><br>
<br><font color="#e78608">------解决方案--------------------</font><br>"/>(.*?)<font color="#e78608">------解决方案--------------------</font><br>
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PHP code

$str = "name1name2";
preg_match_all('/>([^print_r($matches[1]);
/**
输出结果:
Array ( [0] => name1 [1] => name2 )
*/

------解决方案--------------------
$str="name1name2";
preg_match_all("/([^]*)/",$str,$matches);
echo $matches[1][0];
echo $matches[1][1];
?>
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