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求教,数组排序解决思路

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Release: 2016-06-13 13:44:52
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求教,数组排序
有一数组, 想要根b1和a进行二次排序,当b1不同时,按b1正序排列,当b1相同时,按a正序排列。要求效率要高。

PHP code
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array(
    [0] = array(
        ['a'] = 323,
        ['b'] = array(
            ['b1'] = 1
            )
        )    
    [1] = array(
        ['a'] = 234,
        ['b'] = array(
            ['b1'] = 1
            )
        )
    [2] = array(
        ['a'] = 135,
        ['b'] = array(
            ['b1'] = 2
            )
        )
)

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------解决方案--------------------
这意思?
PHP code
<?php function cmp($a,$b){
    return $a['b']['b1'] == $b['b']['b1']?($a['a'] - $b['a']):($a['b']['b1'] - $b['b']['b1']);
}

$array = array(0=>array('a'=>323,'b'=>array('b1'=>1)),
               1=>array('a'=>324,'b'=>array('b1'=>1)),
               2=>array('a'=>135,'b'=>array('b1'=>2)),
);

usort($array,'cmp');
var_export($array);
<br><font color="#e78608">------解决方案--------------------</font><br>
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这意思?

PHP code
function cmp($a,$b){
return $a['b']['b1'] == $b['b']['b1']?($a['a'] - $b['a']):($a['b']['b1'] - $b['b']['b1']);
}

$array = array(0=>array('a'=>323,'b'=>array('b1'=>1)……
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