mysql 的查询嵌套有关问题

WBOY
Release: 2016-06-13 13:25:16
Original
640 people have browsed it

mysql 的查询嵌套问题。

SQL code
 select a.*, d.sell_count from borough as a left join ( select da.* from ( select count(db.id) as sell_count,db.borough_id from housesell as db where db.borough_id = a.id ) as da ) as d where a.is_checked = 1 order by id desc LIMIT 0, 10
Copy after login


请问,left join 里面的
where db.borough_id = a.id 这一句会报错。请问大家有什么方式来实现嘛。



------解决方案--------------------
把ORDER BY a.id 改成group by
SQL code
SELECT a.*, COUNT(db.id) AS sell_count FROM borough AS a LEFT JOIN housesell AS db ON( db.borough_id = a.id) WHERE a.is_checked = 1 GROUP BY a.id ORDER BY id DESC LIMIT 0, 10 
Copy after login
Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!