Community Learn Tools Library Leisure
search
English
Home > Backend Development > PHP Tutorial > 检测客户端,该怎么处理

检测客户端,该怎么处理

WBOY
Release： 2016-06-13 12:06:48
Original
723 people have browsed it

检测客户端
我服务端发送json 发给客户端 如果客户端有回应 就代表客户端没断线

这个逻辑什么写 

PHP貌似没有类似$.post这种东西吧
------解决思路----------------------
服务端不能主动发送数据给客户端，所以你的问题无解

Related labels：
json nbsp php post
source：php.cn
Previous article：请教新建字段时候语句`aaa` varchar(11) NOT NULL，中的NOT NULL有什么作用呢 Next article：怎么检查到一篇文章中有连结就自动加上标签
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Latest Issues
function_exists() cannot determine the custom function Function test () {return true;} if (function_exists ('test')) {echo "test is function...
From 2024-04-29 11:01:01
0
2
1429
There is no output in the parent window document.onclick = function(){ window.opener.document.write('I am the output of the child ...
From 2024-04-18 23:52:34
0
1
1284
PX automatic conversion to REM error  <style>html {   font-size: calc(100vw / 3.75);      }...
From 2024-04-16 09:34:16
0
0
4687
Related Topics
More>
Popular Recommendations
Popular Tutorials
More>
Related Tutorials
Popular Recommendations
Latest courses
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template