请问用名称调用函数和传参-PHP Tutorial-php.cn

请问用名称调用函数和传参

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Release： 2016-06-13 11:26:33

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请教用名称调用函数和传参
会用call_user_func_array调用已知名称的函数, 但调用已实例化的类就不会了...

<br />	class class_a<br />	{<br />		public $var_a	= 0;<br />		<br />		public function fun_1 ( $var )<br />		{<br />			var_dump( $this->var_a + $var );<br />		}<br />	};<br />	<br />	$obj_a	= new class_a();<br />	$obj_a->var_a	= 6;<br />	<br />	call_user_func_array( array( 'class_a', 'fun_1' ), array( 5 ) );<br />

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这样会报两个错, 1个说是call_user_func_array调用了非静态方法, 2个是this不能出现在未实例化的类里
其实在call_user_func_array里出现这两个错误都很好理解...
那有其它方法可以实现利用函数名调用已实例化的类的成员函数, 并且传不定个数的参数么...

call_user_func_array 传参

Related labels：

array class nbsp var

source：php.cn

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