In Java, when working with strings that contain embedded whitespace, achieving a desired format often becomes necessary. Take, for instance, the following string:
mysz = "name=john age=13 year=2001";
Your goal is to modify this string by removing all instances of whitespace while preserving other characters, resulting in the following output:
mysz2 = "name=johnage=13year=2001"
While the trim() method successfully eliminates leading and trailing whitespace from strings, it falls short when dealing with whitespace embedded within the string. Similarly, using replaceAll("\W", "") removes not only whitespace but also the '=' separators.
To effectively achieve your desired result, consider employing the following approaches:
Using replaceAll("\s ", ""):
This regular expression will replace all consecutive sequences of whitespace characters with an empty string. This approach offers a straightforward solution and provides the intended result.
Using replaceAll("\s", ""):
Alternatively, you can use a more concise regular expression that matches and replaces every whitespace character, regardless of whether it is consecutive or not. While both methods produce the same result, the latter option is slightly faster, especially when dealing with strings with a substantial number of consecutive spaces.
Remember, to preserve the modified string value, you can assign it to a variable:
st = st.replaceAll("\s+", "");
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