How to correctly parse JSON data in Golang?

王林
Release: 2024-06-03 20:06:00
Original
643 people have browsed it

Parsing JSON data in Golang can be done through the following steps: Use the encoding/json package. Use json.Marshal() to convert the data structure into JSON byte slices. Use json.Unmarshal() to parse JSON data.

如何正确解析 Golang 中的 JSON 数据?

How to correctly parse JSON data in Golang

In Golang, parsing JSON data is a common task. Here are the steps on how to correctly parse JSON data:

1. Use the encoding/json package

Golang provides encoding/json Built-in package to handle JSON data.

2. Marshal JSON data

If you have any type of data structure, you can use the json.Marshal() function to convert it to JSON byte slice:

import "encoding/json"

type Person struct {
    Name string
    Age  int
}

p := Person{"Alice", 25}

data, err := json.Marshal(p)
if err != nil {
    // 处理错误
}
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3. Unmarshal JSON data

To parse JSON data, you can use the json.Unmarshal() function:

import "encoding/json"

type Person struct {
    Name string
    Age  int
}

var data []byte // JSON 字节切片

var p Person
err := json.Unmarshal(data, &p)
if err != nil {
    // 处理错误
}
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Practical case

Suppose you have a JSON file containing user information:

{
    "users": [
        {
            "name": "Alice",
            "age": 25
        },
        {
            "name": "Bob",
            "age": 30
        }
    ]
}
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To parse this file, you can follow these steps:

  1. Read file content:
import "io/ioutil"

data, err := ioutil.ReadFile("users.json")
if err != nil {
    // 处理错误
}
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  1. Unmarshal JSON data:
import "encoding/json"

type User struct {
    Name string
    Age  int
}

var users []User
err := json.Unmarshal(data, &users)
if err != nil {
    // 处理错误
}
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  1. Now you can accessusers A single user object in the slice.

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