js获取对象为null的解决方法_javascript技巧

WBOY
Release: 2016-05-16 17:13:18
Original
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页面上动态输出的数据,这是ajax获取的数据我要在页面上展示

复制代码代码如下:

success:function(data){
var arr = data.split('_');
var numArr = arr[0].split(",");
var numStr = "";
if(numArr.length==undefined || numArr.length==0){
$("#phonenolist").html('对不起,没有查询到相应的号码!');
}else{
for(var i=0;i numStr += "
  • + numArr[i].toString()+",n_"+i+");\" class='buy'>"
    + numArr[i].toString().substring(0, 3)
    + ""
    + numArr[i].toString().substring(3, 7) + " "
    + numArr[i].toString().substring(7, 11)
    + "
  • ";
    }
    $("#phonenolist").html(numStr);
    }
    index = arr[1];
    total = arr[2];
    $("#curr").html(' 第'+index+'页,共'+total+'页 ');
    }
    function choose_mobile(num,id){
    alert(num+" "+id);
    $("#mobile").val(num);
    $("#xhmobile").html("

    "+num+"

    ");
    $("#"+id).addClass("buy").siblings().removeClass("buy");
    }

    在js里面我的参数大概是这样子,choose_mobile(号码,对象id),但是在执行js的时候只弹出了号码,没有id,这样我很郁闷,后来又请教别人,在代码第9,10行,给方法的两个参数加上了‘'单引号,
    复制代码代码如下:

    就这样成功了,之前让我好纠结,js对字符串的解析跟对数字串的解析还是不太一样啊,分的这么清
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