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Method to add additional parameters to jquery's ajaxfileupload_jquery

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Release： 2016-05-16 16:57:18

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How to say it directly:

Copy code The code is as follows:

$.ajaxFileUpload({
data:{" a":123,"b":456};//Additional parameters, json format
});

Then modify the two functions in the ajaxFileUpload.js file. In fact, It’s just a function (add new parameters to the function)

First place:

Copy code The code is as follows:

createUploadForm: function(id , fileElementId,data){} is greater than line 26.

Then add the following code to the function body:

Copy the code The code is as follows:

if (data) {
for (var i in data) {
$(' }
}

Code function: Process json data and add input of type='hidden' to the form

Second place:

Copy code The code is as follows:

ajaxFileUpload(){} 
var form = jQuery.createUploadForm(id, s.fileElementId,s.data); Just modify this line, just add one more parameter. 

The modification here is actually about the parameters of the function call.

Related labels：

ajaxfileupload

source：php.cn

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