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php下将图片以二进制存入mysql数据库中并显示的实现代码

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Release: 2016-06-06 20:34:11
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php把图片存入mysql教程数据库教程中并在网页上显示,一般情况下并不需要将突破保存到数据库中,不论是异地备份还是什么的,都很麻烦,特殊需要的除外。

//保存图片到数据库的php代码
代码如下:
If($Picture != "none") {
$PSize = filesize($Picture);
$mysqlPicture = addslashes(fread(fopen($Picture, "r"), $PSize));
mysql_connect($host,$username,$password) or die("Unable to connect to SQL server");
@mysql_select_db($db) or die("Unable to select database");
mysql_query("INSERT INTO Images (Image) VALUES ($mysqlPicture)") or die("Cant Perform Query");
}else {
echo"You did not upload any picture";
}

//以img标签读取数据库中的图片的代码
代码如下:
mysql_connect($host,$username,$password) or die("Unable to connect to SQL server");
@mysql_select_db($db) or die("Unable to select database");
$result=mysql_query("SELECT * FROM Images") or die("Cant Perform Query");
While($row=mysql_fetch_object($result)) {
echo "php下将图片以二进制存入mysql数据库中并显示的实现代码";

//如secoed.php文件代码如下
$result=mysql_query("SELECT * FROM Images WHERE PicNum=$PicNum") or die("Cant perform Query");
$row=mysql_fetch_object($result);
Header( "Content-type: image/gif");
echo $row->Image;
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