想获取一个网站的网站内容，但总是获取不到该怎么办

 0){ $method = 'POST'; $headers[] = 'X-Requested-With: XMLHttpRequest'; $headers[] = 'Content-Type: application/x-www-form-urlencoded; charset=UTF-8'; } //如果有传递 Cookie if($ck != ''){ $headers[] = 'Cookie: ' . $ck; } //如果有传递 Referer if($referer != ''){ $headers[] = 'Referer: ' . $referer; } $opts = array( 'http' => array( 'method'=> $method, 'header'=> implode("\r\n", $headers) ) ); if(count($data) > 0){ $opts['http']['content'] = http_build_query ($data); } $context = stream_context_create($opts); $html = file_get_contents($url, false, $context); return array( $html,//本次请求得到的HTML $http_response_header//本次请求服务器返回的响应头 ); } //先请求一次, 从响应头中获取 Cookie $data = request('http://www.reg007.com/'); $headers = implode("", $data[1]); preg_match_all('/Set-Cookie: (.+?;)/', $headers, $session); if(count($session) !== 2){ die('获取Cookie失败!'); } $ck = implode(' ', $session[1]);//得到Cookie $data = request('http://www.reg007.com/search?q=981267080-at-qq.com', $ck, 'http://www.reg007.com/'); $html = $data[0];//取出来 HTML preg_match('/var h="(.+?)"/', $html, $h); if(count($h) !== 2){ die('获取Ajax请求Token失败!'); } $h = $h[1]; $ck .= ' q=' . urlencode('981267080@qq.com'); //这个查询比较耗时, 会有点慢 $data = request( 'http://www.reg007.com/search/ajax', $ck, 'http://www.reg007.com/', array( 'q'=>'981267080@qq.com', 'h'=>$h, 'i'=>0, 't'=>0 ) ); $result = json_decode($data[0]); var_dump($result);