数据的格式是这样的:

{
    "_id" : 1,
    "people_id" : 1,
    "albums" : [
        {
            "id" : 1,
            "name" : "123",
            "privilege" : 0,
        },
        {
            "id" : 2,
            "name" : "Q",
            "privilege" : 5,
        },
        {
            "id" : 3,
            "name" : "Q",
            "privilege" : 5,
        },
    ]
}

{
    "_id" : 2,
    "people_id" : 2,
    "albums" : [
        {
            "id" : 1,
            "name" : "4",
            "privilege" : 0,
        },
        {
            "id" : 2,
            "name" : "5",
            "privilege" : 0,
        }
    ]
}

现在我想的是
1 , 查询people_id 为 1 且 privilege 为 5的内嵌文档,mongodb的查询命令怎么写的啊

2,更新people_id 为 2 且权限为 id为2的内嵌文档的name字段值为 6,更新命令怎么写的啊

查询我用
db.find({"people_id" : 1,"albums":{"$elemMatch" : {"privilege" : 5}}})
来尝试匹配过,但是匹配出了:

{
    "_id" : 1,
    "people_id" : 1,
    "albums" : [
        {
            "id" : 1,
            "name" : "123",
            "privilege" : 0,
        },
        {
            "id" : 2,
            "name" : "Q",
            "privilege" : 5,
        },
        {
            "id" : 3,
            "name" : "Q",
            "privilege" : 5,
        },
    ]
}

我并不想要id为1的那个,只想唯一匹配id为2和3那个

修改,我确实不会,
还请大家帮忙提下解决方法,非常谢谢咯!