1.我写了个爬虫去爬取页面，成功的拿到了所有图片的网络地址2.下载保存到本地后，我去打开图片，发现一只在转圈无法打开]2]
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已经解决，自己找到了方法'''with open(os.path.join(filename, image_name), 'wb') as fs:
fs.write(r.content) fs.close
'''
有可能触发了反爬虫机制或者 URL 不对，导致下载下来的实际是文本文件。用文本编辑器打开看看内容？
requests文档：
In general, however, you should use a pattern like this to save what is being streamed to a file:
with open(filename, 'wb') as fd: for chunk in r.iter_content(chunk_size): fd.write(chunk)
测试：
with open('./pic2/'+str(self.picnum)+'.jpeg', 'wb') as fd: for chunk in r.iter_content(): fd.write(chunk) print('第%s图片下载成功。' % self.picnum)
]2]
![[Web-Frontend] Node.js-Schnellstart](https://img.php.cn/upload/course/000/000/067/662b5d34ba7c0227.png)
已经解决，自己找到了方法
'''
with open(os.path.join(filename, image_name), 'wb') as fs:
'''
有可能触发了反爬虫机制或者 URL 不对，导致下载下来的实际是文本文件。
用文本编辑器打开看看内容？
requests文档：
In general, however, you should use a pattern like this to save what is being streamed to a file:
测试：