Die Rückruffunktion, die eine anonyme Funktion zurückgibt, gibt bei onClick einen Fehler aus
P粉649990273
P粉649990273 2024-04-02 16:37:57
0
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import React from 'react'

export default function Test() {
  const handleClick = () => (label: string) => {
    console.log('label: ' + label)
  }

  return <button onClick={handleClick('red one')}>click me</button>
}

Der TypeScript-Compiler beschwert sich über meinen Code. Was mache ich falsch?

Type '(label: string) => void' is not assignable to type 'MouseEventHandler<HTMLButtonElement>'.
  Types of parameters 'label' and 'event' are incompatible.
    Type 'MouseEvent<HTMLButtonElement, MouseEvent>' is not assignable to type 'string'.ts(2322)
index.d.ts(1494, 9): The expected type comes from property 'onClick' which is declared here on type 'DetailedHTMLProps<ButtonHTMLAttributes<HTMLButtonElement>, HTMLButtonElement>'

P粉649990273
P粉649990273

Antworte allen(2)
P粉587780103

handleClick 函数不需要任何类型的参数,但您向其传递一个字符串。

应该是:

import React from 'react'

export default function Test() {
  const handleClick = (label: string) => () => {
    console.log('label: ' + label)
  }

  return 
}
P粉378890106

反之亦然

应该是

(label: string) => (e: any) => {

而不是

(e: any) => (label: string) => {
import React from 'react'

export default function Test() {
  const handleClick = (label: string) => (e: any) => {
    console.log('label: ' + label)
  }

  return 
}
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