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Question

Ich bin ein Neuling. Ich versuche, den vollständigen Namen in einer der folgenden Zeilen und ohne Obituaryfor

ObituaryforJohnDoe

JamesMichaelLee

zu finden. Meine Regex sieht so aus. (

(.+?)<\/h1>|

Obituary\sfor\s(.+?)<\/h2>) Was ich bekomme ist immer noch

P粉775788723 · Answer

你能在不使用正则表达式的情况下做这样的事情吗？

/**
 * @description : Function extracts names from html header tags
 * @example : "Obituary for John Doe
James Michael Lee" -> ["John Doe", "James Michael Lee"]
 * @param $html string
 * @return []string : list of full names
*/
function extractFullNames($html) {
    $regex = '/(.*?)/';
    preg_match_all($regex, $html, $matches);
    $names = $matches[1];
    $names = array_map('trim', $names);
    $names = array_map('strip_tags', $names);
    $names = array_map('strtolower', $names);
    $names = array_map('ucwords', $names);
    $names = array_map('removeObituary', $names); 
    return $names;
}

/**
 * @description : Function used to remove "Obituary For" if present
 * @example : "Obituary For John Doe" -> "John Doe"
 * @param $name string
 * @return string : name without "Obituary For"
*/
function removeObituary($name) {
    $name = str_replace("Obituary For ", "", $name);
    return $name;
} 

// Test cases
$html = 'Obituary for John Doe
James Michael Lee';
$names = extractFullNames($html);
$expected = ['John Doe', 'James Michael Lee'];

echo "Expected: " . implode(', ', $expected) . "
";
echo "Actual: " . implode(', ', $names);

P粉394812277 · Answer

条条大路通罗马，你或许可以这样做：

|2>Obituary\sfor\s)\K[^>
请在 regex101 查看此演示。匹配项将位于 $out[0] 中。
\K 重置 开头报告比赛。有关详细信息，请参阅 SO 正则表达式常见问题解答。