Scrapy INSERT in „new_table' nur, wenn in „aktueller Tabelle' kein Datensatz vorhanden ist
P粉122932466
P粉122932466 2024-03-29 19:36:16
0
1
318

Ich habe es mit Website-Scraping versucht. Ich habe die Daten erfolgreich aus der aktuellen Datenbanktabelle gelöscht. Aber ich möchte „new_table“ nur einfügen, wenn der Datensatz nicht in der „aktuellen Tabelle“ existiert

Mein Code ist (Pipeline)

table = 'products' table2 = 'new_products'` def save(self, row): cursor = self.cnx.cursor() cursor.execute("SELECT DISTINCT product_id FROM products;") old_ids = [row[0] for row in cursor.fetchall()] create_query = ("INSERT INTO " + self.table + "(rowid, date, listing_id, product_id, product_name, price, url) " "VALUES (%(rowid)s, %(date)s, %(listing_id)s, %(product_id)s, %(product_name)s, %(price)s, %(url)s)") cursor.execute(create_query, row) lastRecordId = cursor.lastrowid self.cnx.commit() cursor.close() print("Item saved with ID: {}" . format(lastRecordId)) if not product_id in old_ids: create_query = ("INSERT INTO " + self.table2 + "(rowid, date, listing_id, product_id, product_name, price, url) " "VALUES (%(rowid)s, %(date)s, %(listing_id)s, %(product_id)s, %(product_name)s, %(price)s, %(url)s)")

Es funktioniert nicht richtig und es liegt ein Fehler vor.

2022-05-06 12:26:57 [scrapy.core.scraper] ERROR: Error processing {'date': '2022-05-06 12:26:57.575507', 'listing_id': '0190199600119', 'price': '4199.00', 'product_id': '1209298', 'product_name': 'APPLE 11" Magic Türkçe Q Klavye Siyah', 'rowid': 456274953331128512, 'url': 'https://www.mediamarkt.com.tr/tr/product/APPLE%2011%22%20Magic%20T%C3%BCrk%C3%A7e%20Q%20Klavye%20Siyah-1209298.html'} Traceback (most recent call last): File "/usr/lib/python3/dist-packages/twisted/internet/defer.py", line 654, in _runCallbacks current.result = callback(current.result, *args, **kw) File "/usr/local/lib/python3.8/dist-packages/scrapy/utils/defer.py", line 162, in f return deferred_from_coro(coro_f(*coro_args, **coro_kwargs)) File "/root/teknosa/teknosa/pipelines.py", line 28, in process_item self.save(dict(item)) File "/root/teknosa/teknosa/pipelines.py", line 62, in save if not product_id in old_ids: NameError: name 'product_id' is not defined Saving item into db ...

Ich habe eine eindeutige Produkt-ID.

Wenn in der aktuellen Tabelle keine Produkt-ID vorhanden ist, fügen Sie diese Produkt-ID in „neue_Produkte“ ein

Wie macht man das?

Vielen Dank.

Letzte Änderung: Ich erhalte diese Fehlermeldung.

2022-05-07 18:17:11 [scrapy.core.scraper] ERROR: Error processing {'date': '2022-05-07 18:17:11.902622', 'listing_id': '8713439219357', 'price': '99.00', 'product_id': '1175529', 'product_name': 'TRUST 21935 NANGA USB 3.1 Kart Okuyucu', 'rowid': -411152717288573423, 'url': 'https://www.mediamarkt.com.tr/tr/product/TRUST%2021935%20NANGA%20USB%203.1%20Kart%20Okuyucu-1175529.html'} Traceback (most recent call last): File "/usr/local/lib/python3.8/dist-packages/mysql/connector/connection_cext.py", line 523, in cmd_query self._cmysql.query(query, _mysql_connector.MySQLInterfaceError: Duplicate entry '-411152717288573423' for key 'products.rowid' During handling of the above exception, another exception occurred: Traceback (most recent call last): File "/usr/lib/python3/dist-packages/twisted/internet/defer.py", line 654, in _runCallbacks current.result = callback(current.result, *args, **kw) File "/usr/local/lib/python3.8/dist-packages/scrapy/utils/defer.py", line 162, in f return deferred_from_coro(coro_f(*coro_args, **coro_kwargs)) File "/root/teknosa/teknosa/pipelines.py", line 28, in process_item self.save(dict(item)) File "/root/teknosa/teknosa/pipelines.py", line 69, in save cursor.execute(create_query, row) File "/usr/local/lib/python3.8/dist-packages/mysql/connector/cursor_cext.py", line 269, in execute result = self._cnx.cmd_query(stmt, raw=self._raw, File "/usr/local/lib/python3.8/dist-packages/mysql/connector/connection_cext.py", line 528, in cmd_query raise errors.get_mysql_exception(exc.errno, msg=exc.msg, mysql.connector.errors.IntegrityError: 1062 (23000): Duplicate entry '-411152717288573423' for key 'products.rowid'

P粉122932466
P粉122932466

Antworte allen (1)
P粉278379495

如果您只想在不存在的情况下插入,则无需执行您正在执行的操作。无需全选然后查看您要查找的那个是否存在。

您需要的是为表2中的produc_id创建一个唯一索引

然后将代码更改为:

table = 'products' table2 = 'new_products'` def save(self, row): create_query = ("INSERT INTO " + self.table + "(rowid, date, listing_id, product_id, product_name, price, url) " "VALUES (%(rowid)s, %(date)s, %(listing_id)s, %(product_id)s, %(product_name)s, %(price)s, %(url)s)") cursor.execute(create_query, row) lastRecordId = cursor.lastrowid self.cnx.commit() print("Item saved with ID: {}" . format(lastRecordId)) create_query = ("INSERT INTO " + self.table2 + "(rowid, date, listing_id, product_id, product_name, price, url) " "VALUES (%(rowid)s, %(date)s, %(listing_id)s, %(product_id)s, %(product_name)s, %(price)s, %(url)s) ON DUPLICATE KEY UPDATE product_id=product_id") cursor.execute(create_query, row) self.cnx.commit()

如果您使用ON DUPLICATE KEY,当它发现重复行(已存在的product_id)时,系统会尝试将product_id更新为相同的product_id,因此不会生效。

如果设置 autocommit= True,则可以删除这些提交。

编辑

如果正如您在评论中所说,仅当表中不存在时才需要插入新表,您可以像这样更改代码:

您需要更改行old_ids = [row[0] for row incursor.fetchall()]中的变量名称,因为您正在更改row参数的值 2.你的问题出在if语句中,product_id变量不存在,需要修改

table = 'products' table2 = 'new_products'` def save(self, row): cursor = self.cnx.cursor() cursor.execute("SELECT DISTINCT product_id FROM products;") old_ids = [element[0] for element in cursor.fetchall()] create_query = ("INSERT INTO " + self.table + "(rowid, date, listing_id, product_id, product_name, price, url) " "VALUES (%(rowid)s, %(date)s, %(listing_id)s, %(product_id)s, %(product_name)s, %(price)s, %(url)s)") cursor.execute(create_query, row) lastRecordId = cursor.lastrowid self.cnx.commit() cursor.close() print("Item saved with ID: {}" . format(lastRecordId)) if not row['product_id'] in old_ids: create_query = ("INSERT INTO " + self.table2 + "(rowid, date, listing_id, product_id, product_name, price, url) " "VALUES (%(rowid)s, %(date)s, %(listing_id)s, %(product_id)s, %(product_name)s, %(price)s, %(url)s)")
    Neueste Downloads
    Mehr>
    Web-Effekte
    Quellcode der Website
    Website-Materialien
    Frontend-Vorlage
    Über uns Haftungsausschluss Sitemap
    Chinesische PHP-Website:Online-PHP-Schulung für das Gemeinwohl,Helfen Sie PHP-Lernenden, sich schnell weiterzuentwickeln!