Wie aktualisiere ich die JSON-Datentypspalte in MySQL 5.7.10?
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P粉512363233 2023-10-16 19:03:34
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Ich habe vor kurzem angefangen, MySQL 5.7.10 zu verwenden, und mir gefällt der native JSON-Datentyp sehr gut.

Aber ich habe ein Problem beim Aktualisieren des JSON-Typwerts.

Frage:

Das Folgende ist ein Tabellenformat, in dem ichdata列中为t1表添加 1 个键。现在我必须获取值修改它并更新表。所以就涉及到一个额外的SELECTAnweisungen verwenden möchte.

Ich kann es so einfügen

INSERT INTO t1 values ('{"key2":"value2"}', 1); mysql> select * from t1; +--------------------+------+ | data | id | +--------------------+------+ | {"key1": "value1"} | 1 | | {"key2": "value2"} | 2 | | {"key2": "value2"} | 1 | +--------------------+------+ 3 rows in set (0.00 sec) mysql>Show create table t1; +-------+------------------------------------------------------------- -------------------------------------------------------+ | Table | Create Table | +-------+--------------------------------------------------------------------------------------------------------------------+ | t1 | CREATE TABLE `t1` ( `data` json DEFAULT NULL, `id` int(11) DEFAULT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1 | +-------+--------------------------------------------------------------------------------------------------------------------+ 1 row in set (0.00 sec)

Gibt es eine Lösung?

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P粉512363233

Antworte allen (2)
P粉012875927

现在使用 MySQL 5.7.22+,可以非常简单直接地在单个查询中更新 json 的整个片段(多个键值,甚至嵌套),如下所示:

update t1 set data = JSON_MERGE_PATCH(`data`, '{"key2": "I am ID2", "key3": "I am ID3"}') where id = 2;

希望它可以帮助访问此页面并寻找“更好”的JSON_SET:) 有关JSON_MERGE_PATCH的更多信息请参见此处:https://dev.mysql .com/doc/refman/5.7/en/json-modification-functions.html#function_json-merge-patch

    P粉035600555

    感谢@wchiquito 为我指明了正确的方向。我解决了这个问题。这是我的做法。

    mysql> select * from t1; +----------------------------------------+------+ | data | id | +----------------------------------------+------+ | {"key1": "value1", "key2": "VALUE2"} | 1 | | {"key2": "VALUE2"} | 2 | | {"key2": "VALUE2"} | 1 | | {"a": "x", "b": "y", "key2": "VALUE2"} | 1 | +----------------------------------------+------+ 4 rows in set (0.00 sec) mysql> update t1 set data = JSON_SET(data, "$.key2", "I am ID2") where id = 2; Query OK, 1 row affected (0.04 sec) Rows matched: 1 Changed: 1 Warnings: 0 mysql> select * from t1; +----------------------------------------+------+ | data | id | +----------------------------------------+------+ | {"key1": "value1", "key2": "VALUE2"} | 1 | | {"key2": "I am ID2"} | 2 | | {"key2": "VALUE2"} | 1 | | {"a": "x", "b": "y", "key2": "VALUE2"} | 1 | +----------------------------------------+------+ 4 rows in set (0.00 sec) mysql> update t1 set data = JSON_SET(data, "$.key3", "I am ID3") where id = 2; Query OK, 1 row affected (0.07 sec) Rows matched: 1 Changed: 1 Warnings: 0 mysql> select * from t1; +------------------------------------------+------+ | data | id | +------------------------------------------+------+ | {"key1": "value1", "key2": "VALUE2"} | 1 | | {"key2": "I am ID2", "key3": "I am ID3"} | 2 | | {"key2": "VALUE2"} | 1 | | {"a": "x", "b": "y", "key2": "VALUE2"} | 1 | +------------------------------------------+------+ 4 rows in set (0.00 sec)

    编辑: 如果要添加数组,请使用JSON_ARRAY就像

    update t1 set data = JSON_SET(data, "$.key4", JSON_ARRAY('Hello','World!')) where id = 2;
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