# coding: utf8
import time
timestamp = time.time() - 3600   # 时间戳
print(time.strftime('%Y{y}%m{m}%d{d} %H{H}%M{M}', time.localtime(timestamp)).format(y='年', m='月', d='日', H='时', M='分'))

还真被我研究出来种万能方法，据我百度Google貌似这还是世上独一份？

话不多说，下面上解决原理及方案：

官方文档：https://docs.python.org/3/lib...

class time.`struct_time`¶

The type of the time value sequence returned by gmtime(), localtime(), and strptime(). It is an object with a named tuple interface: values can be accessed by index and by attribute name. The following values are present:

Note that unlike the C structure, the month value is a range of [1, 12], not [0, 11].
In calls to mktime(), tm_isdst may be set to 1 when daylight savings time is in effect, and 0 when it is not. A value of -1 indicates that this is not known, and will usually result in the correct state being filled in.
When a tuple with an incorrect length is passed to a function expecting a struct_time, or having elements of the wrong type, a TypeError is raised.

看文档可以得知time.localtime()返回的元组结构，我要用到的是年月日时分，前5个，于是乎，代码：

import time
print('%s年%s月%s日 %s时%s分' % time.localtime(1497254119.69407)[:5])

输出：

2017年6月12日 15时55分

搞定。

转载请注明出处，谢谢。