Berechnen Sie die Anzahl der Zeichenfolgen, die mit Zeichen verkettet werden sollen, deren Häufigkeit größer ist als die Summe der Häufigkeiten anderer Zeichen

Let us take the input array 
arr[]: {“xyz", “yyyyx", “q”}

Output obtained is: 3

Let us take the input array 
arr[]: {“mnoml", “lmll", “nln”, "mnlmn"}

Output obtained is : 2

#include <stdio.h>
#include <stdlib.h>
//input strings to be non-empty and not more //than 100 characters
#define MAX_STR_LEN 100

// Function to determine the frequencies of all the characters and reducing the sum of other frequencies in the strings
int* frequency(char** a, int len, char c){

   // We use array to store the frequency
   int* v = (int*)calloc(len, sizeof(int));
   if(v == NULL) {
      printf("Error: Memory allocation failed");
      exit(1);
   }
   
   // Iterating the array a of strings
   for (int i = 0; i < len; i++) {
      char* str = a[i];
      
      // defining an integer variable for storing //the frequencies
      int net_fre = 0;
      
      // Iterating through the string str
      for (int j = 0; str[j] != '\0'; j++) {
      
         // If str[j] is equal to the current character increment the net_fre by 1
         if (str[j] == c)
            net_fre++;
            
         // otherwise decrement net_fre by 1
         else
            net_fre--;
      }
      
      // After iterating the string store this frequency in the array v
      v[i] = net_fre;
   }
   
   //return the array v
   return v;
}

// Function to determine the count of the longest or the lengthiest string that could be obtained from the given array of strings
int longestConcatenatedString(char** a, int len){

   // An integer variable to store the maximum count Also it is set to zero
   int mxm = 0;
   
   // Iterating through all of the alphabets
   for (char c = 'a'; c <= 'z'; c++) {
   
      // Array to store the net_frequency of the character c after reducing the sum of every other frequencies in all of the strings
      int* v = frequency(a, len, c);
      
      // Array is stored in the order of descendants
      for (int i = 0; i < len - 1; i++) {
         for (int j = i + 1; j < len; j++) {
            if (v[i] < v[j]) {
               int temp = v[i];
               v[i] = v[j];
               v[j] = temp;
               char* temp_str = a[i];
               a[i] = a[j];
               a[j] = temp_str;
            }
         }
      }
      
      // Variable res is defined to store the //result
      int res = 0;
      int sum = 0;
      for (int i = 0; i < len; i++) {
         sum += v[i];
         
         // If sum is greater than 0 then increment res by 1
         if (sum > 0) {
            res++;
         }
      }
      
      // Keeping the track of the maximum one
      mxm = mxm > res ? mxm : res;
      free(v);
   }
   
   // Returning the maximum value obtained
   return mxm;
}
int main(){
   char* a[] = { "mnoml", "lmll", "nln", "mnlmn" };
   printf("Count of strings to be concatenated with a character having frequency greater than sum of others: ");
   int len = sizeof(a) / sizeof(a[0]);
   printf("%d", longestConcatenatedString(a, len));
   return 0;
}

Count of strings to be concatenated with a character having frequency greater than sum of others: 2