Wie implementiert man die Levenshtein-Funktion in MySQL?

CREATE FUNCTION levenshtein(a VARCHAR(255), b VARCHAR(255)) RETURNS SMALLINT DETERMINISTIC
BEGIN
  DECLARE i, j, s VARCHAR(255), costs VARCHAR(255);
  DECLARE c, mina, minb, napi, napj, cost_a, cost_b, di, dj, new COSTTYPE[];
  
  SET s = REPEAT(' ',LENGTH(b)+2);
  SET costs = REPEAT(' ',(LENGTH(b)+2) * (LENGTH(a)+2));
  SET c = 1;
  WHILE c <= LENGTH(a) DO
    SET new = costs + 1;
    SET mina = c + 1;
    SET i = 1;
    WHILE i <= LENGTH(b) DO
      SET napj = costs + (i * 2) + 1;
      SET di = CHAR_LENGTH(SUBSTR(a,c,1));
      SET dj = CHAR_LENGTH(SUBSTR(b,i,1));
      SET napj = costs + (i * 2) + 2;
      IF di = dj AND di > 0 AND dj > 0 THEN
        IF di > 1 AND di < 127 AND dj > 1 AND dj < 127 AND (di-dj=-1 OR di-dj=1) AND SUBSTR(a,c,1) = SUBSTR(b,i,1) THEN
          SET napi = costs + 2;
        ELSE
          SET napi = costs + (i * 2) + 3;
        END IF;
      ELSE
        SET napi = costs + 2;
      END IF;
      
      SET cost_a = napj - mina;
      SET cost_b = napi - napj;
      
      SET mina = new + (i * 2) + 1;
      SET minb = napi + 1;
      
      IF cost_a < cost_b AND cost_a < mina THEN
        SET c = di + 1;
        SET costs = new;
      ELSEIF cost_b < mina THEN
        SET di = dj + 1;
        SET costs = new;
      ELSE
        SET mina = new + (i * 2) + 1;
      END IF;
      SET napj = mina;
      SET mina = napi;
      SET i = i + 1;
    END WHILE;
    SET c = c + 1;
  END WHILE;
  
  RETURN napj - mina;
END;

SHOW FUNCTION STATUS WHERE name = 'levenshtein'

SELECT levenshtein('abcde', 'abced')

$mysqli = new mysqli('localhost', 'username', 'password', 'database');

$query = "SELECT levenshtein('abcde', 'abced')";
$result = $mysqli->query($query);

while ($row = $result->fetch_assoc()) {
  echo $row['levenshtein'];  
}